Let n be divisible by 17 . So n is of the form 17k . 17k +1 is divisible by 13 so 4k +1 is divisible by 13 . So k is 3 is a solution or any multiple of 13 plus 3. Say $k=13 t +3$ or $n =221t +51$
some short and selected math problems of different levels in random order I try to keep the ans simple
Tuesday, March 10, 2026
2026/021) Let a,b,c be integers satisfying $ab+bc+ca=1$. Prove that $(1+a^2)(1+b^2)(1+c^2)$ is a perfect square.
We have putting $ab +bc +ca$ for 1 in $1+a^2$
$1+a^2 = ab + bc +ca + a^2 = (a+b)(a+c)$
Similarly $1+b^2 = (b+c)(b+a)$
And $1+ c^2 = (c+b)(c+a)$
So $(1+a^2)(1+b^2)(1+c^2) = ((a+b)(b+c)(c+a))^2$ a perfect square
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