Sunday, June 5, 2011

2011/056) Find lim n-> inf (n/(n+2))^n

(n/(n+2))^n
= (1/(1+2/n)^n
= ((1/(1+2/n)^n/2)^2

As (1+1/x) ^x as x -> infinite is e so /(1+2/n)^n/2 = e so given limit = 1/e^2

No comments: