we have
x+ 3 = (x+1) + 2
as f(x+1) = 2x^2 -11x+3
so f(x+3) = 2(x+2)^2 - 11(x+ 2) + 3 = 2(x^2 + 4x + 4) - 11(x+2) + 3 = 2x^2 -3x - 11
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(rationale
f(x+1) = 2x^2 - 11x + 3
let x + 1 = y
so f(y) = 2(y-1) ^2 - 11y + 3
so f(y+2) = 2(y+1)^2 - 11(y+1) + 3
hence f(x+3) = 2(x+2)^2 - 11(x+2) + 3)
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