we have
cos 2 t = 1 - 2 sin ^2 t
so if sin 1 is rational cos 2 is rational
now cos 0 =1 is rational
cos (n-2 ) + cos (n+2) = 2 cos n cos 2
so cos (n+2) = - cos (n-2) + 2 cos n cos 2
if cos n and cos n- 2 are rational then by strong induction cos n+2 is rational
hence proceeding we get cos 30 = sqrt(3)/2 is rational which is contradiction
hence cos 2 and then sin 1 are not rational
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