(2−√(2+x))/((2^(1/3)−(4−x)^(1/3))
Solution:
I would rationalize the denominator to get
(2−√(2+x))(2^(2/3) + 2^(1/3) (4-x)^(1/3) + (4-x)^(1/3)) /( 2 – (4-x))
Now 2- (4-x) = - ( 4- (2+x) = - (2−√(2+x))( (2+√(2+x))
So we get - (2^(2/3) + 2^(1/3) (4-x)^(1/3) + (4-x)^(1/3))/ ((2+√(2+x))
Putting x =2 we get - (2^(2/3) + 2^(2/3) +
2^(2/3))/( 2 + 2) = - 3 * 2^(2/3) / 4
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