As q and r are real and
α +i β is a root so α - i β is a
root.
Now sum of roots = (coefficient of x^2 =) 0)
Now sum of roots = (coefficient of x^2 =) 0)
Ler 3rd root be γ, so γ + (α +i β) + (α- i β) = γ
+ 2 α = 0
Or γ = - 2 α
So - 2 α is root of
f(x) = x^3 + qx +r =0
So 2 α is root of
f(-x) = - x^3 – q x + r = 0 or x^3 + qx – r = 0
equation x^3 + qx - r = 0
1 comment:
good sum
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