2014/055) show that 6^33 > 3^33 + 4^33 + 5^33

we have
6^3 = 3^3 + 4^3 + 5^3

raising both sides to 11th power

6^33 = (3^3+4^3+5^3)^11 > (3^3)^11 + (4^3)^11 + (5^3)^11 or 3^33 + 4^33 + 5^33