Without loss of generality let us assume that a > b>c
So a^n < b^n + c^n
Or 1 < (\frac{b}{a})^n + (\frac{c}{a})^n
If a>b > c then (\frac{b}{a})^n = 0 and (\frac{c}{a})^n =0 when n goes to infinite
So 1 < 0 which is contradiction
So b has to be same as a for the sum to be 1 in the limit
Or the triangle is isosceles
Proved
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