For eah dice there are 6 outcomes
for 7 dices there are 6^7 outcomes
so there are 5^7 out comes
10 can come in followin ways
6 ones and a 4 this can come in 7 ways(4 at any of 7 places)
5 ones one 2 and one 3 this can come in 7 * 6 = 42 ways( 2 at any of 7 places and and then 3 in any of the next 6 paces)
4 ones and 3 twos = 7 \choose 3 = 35 places
so total number of places = 7 + 42 + 35 = 84.
so probability = \frac{84}{6^7}
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