we can solve by fining GCD of 2 and 3 but here I shall solve it by a different approach
We can rewrite this as
$3y = 2x -8$
RHS is even so LHS should be even or y should be even
So let $y =2k$
We get $6k = 2x -8$
Or x = $3k + 4$
So $x = 3k + 4$ and $y = 2k$ are parametric form of solution
by choosing any integer for k we can get particular solution
k = 1 gives (7,2)
k =2 gives (10,4)
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