2026/032) The graph of $x^2−4y^2=0$ is: (A) a parabola (B) an ellipse (C) a pair of straight lines (D) A point

We have $x^2–4y^2=0$

Or $(x-2y) (x+2y) = 0$

Hence $x-2y = 0$ (this is a straight line)   or $x + 2y = 0$ (this is another straight line)

Hence ans is (C) A pair of straight lines