the total number of integer pairs (x, y) satisfying the equation x + y = xy is
a) 0
b) 1
c) 2
d) 3
None of these
we have x+y- xy = 0
subtract 1 from each side
x+y - xy - 1 = - 1
x(1-y) + (y-1) = -1
or (x-1)(1-y) = - 1
so x-1 = 1 and 1-y = -1 => x = 2 and y= 2
or x-1 = - 1 and 1- y = 1 => x= 0 and y =0
so 2 pairs
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