Wednesday, July 24, 2013

Q13/073) Solve x^3−3x=√(x+2)



If we square both sides( I am not squaring to find the expression) then
we get x 6th order polynomial the coefficient of x^6 is 1 and constant term of is -2 as x+2 goes to left
so if it has a rational root it is factor of -2 that is 1/-1/2/-2
1 and -1 can be ruled out as they give give irrational so checking - 2 and 2 we get that x= 2 satisfies both sides
hence it is a root.
to find all solutions is a different matter ( others are irrational)


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