Q13/101) Solve : 36/x^(1/2) + 9/y^(1/2) = 42 – 9 x^(1/2) – y^(1/2)

36/x^(1/2) + 9x^(1/2) + 9 /y^(1/2) + y^(1/2) = 42

Hence

(36/x^(1/2) + 9x^(1/2) – 36) + (9 /y^(1/2) + y^(1/2)- 6) = 0

Hence 9( 2/x^*1/4 – x^(1/4))^2 + (3/y^(1/4)  – y^(1/4))^2 = 0
=> 2/x^(1/4) – x^(1/4) -= 0 or x = 2^2 = 4

And  3/y^(1/4)  – y^(1/4) = 0 or y = 9