Q13/111) Given the system of equation below: a+2b+3c+4d=262 ..1 4a+b+2c+3d=123 ..2 3a+4b+c+2d=108 ..3 2a+3b+4c+d=137 .. 4 Evaluate 27a+28b+29c+30d.

Adding all (4) we get

10(a+b+c+d)=630 and this gives a+b+c+d=63…(5)

Mulitply (5) by 26 and add (1) to get

27a+28b+29c+30d = 63 * 26 + 262= 1900