Q13/129) What is the value of x in the following equation : (ab)^2 = (bc)^4 = (ca)^x = abc

From (ab)^2= abc we have ab = (abc)^(1/2)

Similarly (bc) = (abc)^(1/4)

ca = (abc)^(1/x)

multiplying all 3 we get (abc)^2 = (abc)^(1/2+1/4 + 1/x)

or 2 = ½ + ¼ + 1/x or x = 4/5