Q13/130) For real numbers a,b what is max(a,b)+min(a,b)

It is a + b

To prove there are 3 cases

1) a >b

In this case max(a,b) = a and min (a,b) = b and so sum = a +b

2) a= b

In this case max(a,b) = min (a,b) = a and so sum = 2a and a+ b= 2a

3) a < b

In this case max(a,b) = b and min (a,b) = a and so sum = a +b

so in call cases sum = a + b