2014/039) Find x,y

(x+1)^(1/2) + (y+1)^(1/2) = 3

                xy – x – y + 15 = 0

I copy the 1st equation

(x+1)^(1/2) + (y+1)^(1/2) = 3

The second equation given

xy–x–y+1+14=0
Or
(x−1)(y−1)=−14...(2)

One one of (x-1) and (y-1) is –ve
As it is symmetric in xand y we can assume x to be so
So x – 1 = - 14 or -2 or – 1
From the 1st equation x + 1 >= 0 so x >= -1
So x = -1 , 0
X = 0 => y- 1 = 15 so does not satisfy (1)
X= -1 => y = 8 and it satisfiles (1)
So x = -1 , y = 8 or x = 8, y = -1