2014/072) The number of divisiors of the form $4n+ 2(n\ge 0)$ of the integer 240 is

a ) 4
b) 8
c) 10
d) 3

as $240 = 16 * 15 = 2^4 *3 * 5$

in 4n+2 there is one  occurrence of 2 and hence number of factors = 1  * 2 *2 = 4 as 15 has 4 odd factors