Friday, September 30, 2016

2016/088) Which number is smaller $\sqrt{3} + \sqrt{5}$ or $\sqrt{2} + \sqrt{6}$

we have $\sqrt{3} - \sqrt{2}= \frac{1}{\sqrt{3} + \sqrt{2}}$
and  $\sqrt{6} - \sqrt{5}= \frac{1}{\sqrt{6} + \sqrt{5}}$
from the above $\sqrt{3} - \sqrt{2} > \sqrt{6} - \sqrt{5}$
or  $\sqrt{3} + \sqrt{5} > \sqrt{6} + \sqrt{2}$

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