2020/005) Compare $\log_23$ and $\log_35$

We have $2^3=8 < 9 = 3^2$
Hence $2^\frac{3}{2} < 3$
Or $\log_23 > \frac{3}{2}\cdots(1)$
$3^3=27 > 25 = 5^2$
Hence $3^\frac{3}{2} > 5$
Or $\log_35 <  \frac{3}{2}\cdots(2)$
Using (1) and (2) $\log_23 > \log_35$