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Monday, July 8, 2024

2024/044) What is the equation of a circle which passes through three points (0,0), (a,0),(0,b)

 https://www.quora.com/What-is-the-equation-of-a-circle-which-passes-through-three-points-0-0-a-0-and-0-b

Because one point (0,0)  is origin, one point (a,0) lies on x-axis and another (0,b) on y axis it is clear that is is a right angled triangle. so the circumcenter is the midpoint of the hypotenuse that is (\frac{a}{2},\frac{b}{2})

so the equation of the circle is

(x-\frac{a}{2})^2 +(y-\frac{b}{2})^2=(0-\frac{a}{2})^2 + (0-\frac{b}{2})^2   the RHS is square of  distance of origin to to the centre

simplifying we get

x^2-ax+y^2-by=0

 

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