Proof:
A cube is either even or odd
If it is odd we can write it as $2n + 1$ which can be written as $(n+1)^2 - n^2$
If it is even the the number is even say $2n$ so cube is $8k$ where $n= k^3$ can be written as $(2k+1)^2 -(2k-1)^2$
Proof:
A cube is either even or odd
If it is odd we can write it as $2n + 1$ which can be written as $(n+1)^2 - n^2$
If it is even the the number is even say $2n$ so cube is $8k$ where $n= k^3$ can be written as $(2k+1)^2 -(2k-1)^2$
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