We have GCD = $6 = 2 * 3$
$1^{st} number = $12 = 2^2 *3$
$2^{nd}$ number = $18= 2 * 3^2$
LCM = $72 = 2^3 * 3^2$
So the $3^{rd}$ number has to of the form $2^a3^b$
Taking the lowest powers of 2 and 3 we get the HCF
So HCF = $2^{min(1,a)}3^{min(1,b)}= 2 * 3$ which gives $a >=1$ and $b >=1$
Taking the highest powers of 2 and 3 we get the LCM
LCM= $2^{max(2,a)}3^{max(2,b)}= 2^3 * 3^2$ so $a=3$ and $ b <=2$
Giving $a=3,b=1$ that is number = $2^3*3=24$ or $a=3,b=3$ that is number = $2^3*3^2=72$
so $3^{rd}$ number can be 24 or 72
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