Can an infinite arithmetic sequence of positive integers contain exactly one perfect square? If so, which one?
Ans : NO
reason :
if it has one square without loss of generality we can assume that it is the 1st term ( deleting all terms to the left and let it be x^2 and common difference is d
then x^2 + 2dx + d^2 = x^2 + d ( 2x + d)
so the term (2x +d+1)th term is is perfect square
we can generalize if as
x^2 + 2ndx + (nd)^2 = x^2 + d(2nx + n^2d) and putting n = 1 on wards it shall have infinite perfect squares
so if it has at least one perfect square then it shall have infinite perfect squares
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