Sunday, January 8, 2012

2012/004) P(x) = 32 + 80x + 80x^2 + 40x^3 + 10x^4 + x^5

we have
(x+2)^5 = x^5 + 2 * 5x^4 + 2^ 2 * 10x^3 + 2^ 3 * 10 x^2+ 2^4 * 5x + 32
= x^5 + 10x^4 + 40x^3 + 80 x^2+ 80 x + 32
= P(x)

so P(x) = (x+2)^5

so p(-2 + 2i) = (-2 + 2i + 2)^5 = (2i)^5 = 32 i

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