2014/009)Given ab=1 bc=2 cd=3 de=4 ea=5 find a,b,c,d,e

Solution 2014/009)

Multiply all 5 to get (abcde)^2 = 120
Or abcde = +/-120^(1/2)
Devide by product of ab and cd to get e = = +/-120(1/2)/ 3= = +/-(40/3)(1/2) = +/-2(10/3)(1/2)

Similarly you can find the rest. It should be noted that all should be positive or all should be –ve.