Friday, May 23, 2014

2014/047) For how many 2 digit numbers the sum of digits is greater than the product of digits?



(x+y) > xy
or xy - x - y < 0
x(y-1) < y

y = 0 or 1 for all x

x < y/(y-1)

or x < 1+ 1/(y-1)
so x has to be 1

so multiples of 10 or any one of digits sould be 1

that 10, 20, 30, 40,50,60,70,.80,90, 11,12,13,14,15,16,17,18,19, 21,31,41,51,61,71,81,91 that is 26 numbers

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