f1(x)
and f2(x)
must have a common factor. Otherwise g(x) shall be product of f1(x)
and f2(x)
and order 4
let f1(x)
= (x-m)(x-p)
and let f2(x)
= 2(x-m)(x-q)
comparing constant term
of f1(x)
= mp = - a and 2 mq = a we get p = - 2q or m = 0 => a = 0
then taking the product and comparing
coefficient of x
we get m+p = 29-a ...(1)
m – q = (43-2a)/2
or 2m – p = 43 – 2a ... (2)
solving (1) and (2) 3 m = (72-3a) or m
= 24 – a
so p = 2m + 2a – 43 = 48 – 43 = 5
now
- a = mp = 5(24-a) or 4a = 120 or a= 30
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