2014/115) how many factors of 240 are therer which are of the form 4n+ 2

240 can be factored as $2^4 * 3 * 5$

now for a factor to be of the form it should be 2 multiplied by by an odd number,
so it is 1 * (1+1) * (1+1) ( one way of choosing 2, 2 ways of choosing power of 3 ( $3^0, 3^1$) and same way 2 ways of choosing 5) or it is 4