Let $5 \csc\, x - 2 \cot\, x = 5 \cdots (1)$
Then, squaring both
sides
$25 \csc^2 x + 4 \cot^2 x - 20 \csc\, x \cot\, x = 25$
or $25
( \csc^2x - 1 ) + 4 ( \csc^2 x - 1 ) - 20 \csc\, x \cot\, x = 0$
or $25
\cot^2 x + 4 \csc^2 x - 20 \csc\, x \cot\, x = 4$
or $(5\cot\, x - 2 \csc\, x )^2 = 4$
or $5\cot\, x - 2 \csc\, x = \pm 2$
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