Let 5 \csc\, x - 2 \cot\, x = 5 \cdots (1)
Then, squaring both
sides
25 \csc^2 x + 4 \cot^2 x - 20 \csc\, x \cot\, x = 25
or 25
( \csc^2x - 1 ) + 4 ( \csc^2 x - 1 ) - 20 \csc\, x \cot\, x = 0
or 25
\cot^2 x + 4 \csc^2 x - 20 \csc\, x \cot\, x = 4
or (5\cot\, x - 2 \csc\, x )^2 = 4
or 5\cot\, x - 2 \csc\, x = \pm 2
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