The slope of the line $5x-6y
= 30$ say $m_1$ is $\frac{5}{6}$
so slope of the line perpendicular to it say $m_2$ is $\frac{-6}{5}$ as $m_1m_2 = -1$
so equation of line
= $6x + 5y = c# where c is a constant
as y intercept = 2 so y = 2 when x = 0
so it is $6x + 5y = 10$ is the equation
so slope of the line perpendicular to it say $m_2$ is $\frac{-6}{5}$ as $m_1m_2 = -1$
so equation of line
= $6x + 5y = c# where c is a constant
as y intercept = 2 so y = 2 when x = 0
so it is $6x + 5y = 10$ is the equation
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