The slope of the line 5x-6y
= 30 say m_1 is \frac{5}{6}
so slope of the line perpendicular to it say m_2 is \frac{-6}{5} as m_1m_2 = -1
so equation of line
= $6x + 5y = c# where c is a constant
as y intercept = 2 so y = 2 when x = 0
so it is 6x + 5y = 10 is the equation
so slope of the line perpendicular to it say m_2 is \frac{-6}{5} as m_1m_2 = -1
so equation of line
= $6x + 5y = c# where c is a constant
as y intercept = 2 so y = 2 when x = 0
so it is 6x + 5y = 10 is the equation
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