We have f(x) = | x+2 |
or f(x) = x + 2 for x >=-2 and f(x) = -x-2 for x < -2
at x = -2 the right hand limit is 0 and the left hand limit is 0
so it is continuous at x = -2
differentiating from left we get f'(x) = -1 and differentiating from right f'(x) = 1
as left hand derivative and right hand derivative are not same of it is
not differenctiable
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