Let the number of numbers be n and it starts at a
So we have the sum $= an + frac{n(n-1)}{2} = 2024$
Or $2an + n(n-1) = 4048$ and $a\ge 1$
Or $n(2a+n-1)= 4048 = 16 * 253 = 2^4 * 23 *11$
Now out of n and 2a+n-1 one is even and one is odd so n = 16 ( 2a +n -1 = 253) or 1 ( 2a +n -1 = 4048) or 11 ( 2a +n -1 = 368) or 23 ( 2a +n -1 = 176)
Clearly n = 23 is the largest giving 2a + 22 = 176 and a = 77
So largest number of consecutive positive integers is 23 and it starts with 77
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