Loading [MathJax]/jax/element/mml/optable/Latin1Supplement.js

Thursday, October 9, 2014

2014/087) Solve \sqrt{x-2}- \sqrt{x-7}=1

Solution

we are given


\sqrt{x-2}- \sqrt{x-7}=1\cdots (1)

we have (x-2) - (x-7) = 5\cdots(2)

dividing we get

\sqrt{x-2}+ \sqrt{x-7}=5\cdots (3)
adding (1) and (3)

2\sqrt{x-2}=6
or  \sqrt{x-2}=3
or x= 11

No comments: