2014/088) For how many different integral values of b are both roots of $x^2+bx-16=0$ integers?

16 = 1* 16
= 2 * 8
= 4 * 4
= (-1) * (-16)
= (-2) * (-8)
= (-4) * (-4)

there are 6 sets of b as it can be factored in 6 ways

the values being 1+16 = 17, 2+8 = 10, 4 + 4 = 8, -1 - 16 = - 17, -2 -8 = -10 and -4 -4 = =8