Let
us take product of 5 and - 20 (coefficient of $x^2$ and constant)
that is - 100
find -48 and sum of 2 number so that product is -100 ( - 50 and 2 by trial and error). take factors of 100 and find sum
so $5x^2 - 48 x - 20$
= $5x^2 - 50 x + 2x - 20$ now by grouping
= $5x(x-10) + 2(x - 10)$
= $(5x+2)(x-10)$
that is - 100
find -48 and sum of 2 number so that product is -100 ( - 50 and 2 by trial and error). take factors of 100 and find sum
so $5x^2 - 48 x - 20$
= $5x^2 - 50 x + 2x - 20$ now by grouping
= $5x(x-10) + 2(x - 10)$
= $(5x+2)(x-10)$
No comments:
Post a Comment