if is a square let it be $x^2$
$37p + 4= x^2$
or $37p = (x^2-4) = (x-2)(x+2)$
as p is prime so one number is 37 and another is prime or one number is 37p and another number is 1
if x -2 = 1 then x +2 is 5 so it is not 37p
difference between x -2 and x+ 2 is 4 so numbers are 37 and 41 or 37 and 33.
but 33 is not prime so p = 41
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