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Thursday, June 30, 2016

2016/062) If x= 2 + \sqrt[3]{2^2} + \sqrt[3]{2} then the value of x^3 - 6x^2+6x is

we have  x-  2 =  \sqrt[3]{2^2} + \sqrt[3]{2}
hence (x-2)^3 = 4 + 2 + 3 * 2 *(\sqrt[3]{2^2} + \sqrt[3]{2}) = 6 + 3 * 2 (x-2) = 6x - 6
Hence x^3 - 6x^2 + 12x -8 = 6x-6 or x^3-6x^2+6x = 2

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