$1760
= 160 * 11 = 32 * 5 * 11$
$160 = 32 * 5$
32 is the HCF and and one number is 32 * 5
the other number has to be 32m when 32m* 5 = 1760 and m is coprime to 5
so m = 11
so other number = 32 * 11 = 352
$160 = 32 * 5$
32 is the HCF and and one number is 32 * 5
the other number has to be 32m when 32m* 5 = 1760 and m is coprime to 5
so m = 11
so other number = 32 * 11 = 352
This
can also be solved by using the rule that product of HCF and LCM is
the product of numbers
No comments:
Post a Comment